0=3x^2-24x-540

Solution for 0=3x^2-24x-540 equation:

0=3x^2-24x-540

We move all terms to the left:

0-(3x^2-24x-540)=0

We add all the numbers together, and all the variables

-(3x^2-24x-540)=0

We get rid of parentheses

-3x^2+24x+540=0

a = -3; b = 24; c = +540;
Δ = b2-4ac
Δ = 242-4·(-3)·540
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-84}{2*-3}=\frac{-108}{-6}
=+18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+84}{2*-3}=\frac{60}{-6}
=-10
$